By Burichenko V.P.
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Additional resources for 2-Cohomologies of the groups SL (n,q)
35 = 3 · 3 · 3 · 3 · 3 = 243. c. 27 = 2 · 2 · 2 · 2 · 2 · 2 · 2 = 128. d. 28 = 2 · 2 · 2 · 2 · 2 · 2 · 2 · 2 = 256. You already know from part c that 27 = 128, so multiply this number by 2 to get your answer: 128 · 2 = 256. p Find the value of the following powers: a. 104 = 10,000. Write 1 followed by four 0s. b. 1010 = 10,000,000,000. Write 1 followed by ten 0s. c. 1015 = 1,000,000,000,000,000. Write 1 followed by fifteen 0s. d. 101 = 10. Any number raised to the power of 1 is that number. Chapter 3 Getting Down with Negative Numbers In This Chapter ᮣ Understanding negative numbers ᮣ Finding the absolute value of a number ᮣ Adding and subtracting negative numbers ᮣ Multiplying and dividing negative numbers N egative numbers, which are commonly used to represent debt and really cold temperatures, represent amounts less than zero.
And most importantly, you find out how to rewrite equations in alternative forms that allow you to solve problems more easily. Next, I show you how to use parentheses to group numbers and operations together. You discover how the associative property ensures that, in certain cases, the placement of parentheses doesn’t change the answer to a problem. You also work with four types of inequalities: >, <, ≠, and ≈. Finally, I show you that raising a number to a power is a shortcut for multiplication and explain how to find the square root of a number.
20 · 20 = 400 256 < 400, so Guess 15: 256 is between 10 and 20. 15 · 15 = 225 256 > 225, so Guess 16: 256 is between 15 and 20. 16 · 16 = 256 This is correct, so 15. Find the value of the following powers: 16. Find the value of the following powers: a. 6 a. 104 b. 35 b. 1010 c. 27 c. 1015 d. ) d. 101 2 Solve It 256 = 16. Solve It 33 34 Part I: Back to Basics with Basic Math Answers to Problems in Smooth Operators The following are the answers to the practice questions presented in this chapter.
2-Cohomologies of the groups SL (n,q) by Burichenko V.P.